Solving Schrödinger’s Equation for an Infinite Square Well

But instead of getting all fancyy on you, let’s keep it real and solve a simple version: the infinite square well.

To begin with, what is an infinite square well? It’s basically a box with infinitely high walls that confine a particle to move only within its boundaries. Think of it like a tiny room for your cat they can’t escape because the walls are too tall! But in this case, we’re dealing with subatomic particles and not feline friends.

So let’s get down to business. Schrödinger’s Equation looks intimidating at first glance:

𝜁(²ψ/x²) + (2mE/²)ψ = 0

But for our infinite square well, we can simplify it a bit. Since the particle is confined to move only within the box, there’s no need to worry about any external potential energy (V). This means that E is just equal to the kinetic energy of the particle:

E = (1/2)mv²

Now let’s plug in our simplified values into Schrödinger’s Equation. We know that v is constant within the box, so we can take it out of the derivative and get rid of the time-dependent part (since this isn’t a time-dependent problem).

𝜁(²ψ/x²) + (2mE/²)ψ = 0

𝜁(²ψ/x²) (8mE/²a²)ψ = 0

Where a is the width of our box. This looks much better! Now let’s solve for ψ using some fancy math stuff that we won’t go into detail about because it would bore you to tears (trust us, we tried). But here are the results:

ψ = Asin(nπx/a) + Bcos(nπx/a), where n is an integer and A and B are constants.

Solving Schrödinger’s Equation for the infinite square well isn’t as scary as it seems. Just remember to keep your cat inside their box, or else they might escape and cause chaos in your living room.

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